In the diagram, LK is a diameter of the circle with centre P. RNS is a tangent to the circle at N. T is a point on NK and TP ⊥ KL. ∠PLN = x. Diagram
  1. 11.1
    Prove that TPLN is a cyclic quadrilateral
    (3)
    1. 11.2
      Determine. giving reasons, the size of ∠N1 in terms of x.
      (3)
      1. 11.3
        Prove that:
        1. 11.3.1
          ▵KTP ||| ▵ KLN
          (3)
          1. 11.3.2
            KT.KN = 2KT2 - 2TP2
            (5)
          (14)
          [{"prnt":"11","num":"11.1","answer":""},{"prnt":"11","num":"11.2","answer":""},{"prnt":"11.3","num":"11.3.1","answer":""},{"prnt":"11.3","num":"11.3.2","answer":""}]

          Answers

            1. 11.1
            2. 11.2
            3. 11.3.1
            4. 11.3.2
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